(2x+tany)dx+(sec^2y)dy=0

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Solution for (2x+tany)dx+(sec^2y)dy=0 equation:


Simplifying
(2x + tany) * dx + (sec2y) * dy = 0

Reorder the terms:
(anty + 2x) * dx + (sec2y) * dy = 0

Reorder the terms for easier multiplication:
dx(anty + 2x) + (sec2y) * dy = 0
(anty * dx + 2x * dx) + (sec2y) * dy = 0
(adntxy + 2dx2) + (sec2y) * dy = 0

Multiply c2esy * dy
adntxy + 2dx2 + c2desy2 = 0

Reorder the terms:
adntxy + c2desy2 + 2dx2 = 0

Solving
adntxy + c2desy2 + 2dx2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1c2desy2' to each side of the equation.
adntxy + c2desy2 + -1c2desy2 + 2dx2 = 0 + -1c2desy2

Combine like terms: c2desy2 + -1c2desy2 = 0
adntxy + 0 + 2dx2 = 0 + -1c2desy2
adntxy + 2dx2 = 0 + -1c2desy2
Remove the zero:
adntxy + 2dx2 = -1c2desy2

Add '-2dx2' to each side of the equation.
adntxy + 2dx2 + -2dx2 = -1c2desy2 + -2dx2

Combine like terms: 2dx2 + -2dx2 = 0
adntxy + 0 = -1c2desy2 + -2dx2
adntxy = -1c2desy2 + -2dx2

Divide each side by 'dntxy'.
a = -1c2en-1st-1x-1y + -2n-1t-1xy-1

Simplifying
a = -1c2en-1st-1x-1y + -2n-1t-1xy-1

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